Considering how regularly new versions of Firefox now come along, that's quite some bug fix list in version 10! http://t.co/K3I2vLpW 3 days ago

15th
Oct 08

Recording video from a Nintendo DS



My daughter asked me last night if there’s a way to record quality video from a Nintendo DS.

After some digging I found that the only way to connect a DS to a video camera properly involves taking the DS apart, soldering and a general high-knowledge of electronics. My hope was that there some sort of GBA cart that would plug in and provide the facility.

However, I did come across the following video on YouTube which is a simple but genius alternative…

The video cannot be shown at the moment. Please try again later.

This would cover the picture – quality sound that doesn’t pick up your button clicking and nose sniffing can be achieved simply by connecting your DS headphone socket to your PC – you will need to record the video and sound at the same time but from different sources.

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15th
Oct 08

Webpage language translation


Google provide some excellent tools for adding translation facilities to your website. They also provide browser tools so that you can quickly translate a page that you might be on.

With that in mind they’ve taken the appropriate step of adding facilities for web developers to override this.

For example, to stop translation on a section of your site add class="notranslate" to the appropriate tag, such as DIV or SPAN.

To prevent translation on an entire page, add the following to the <HEAD> section…

<meta name="google" value="notranslate">

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15th
Oct 08

Finding the number of users online


I often wondered how sites detected the number of users online. After some digging I’ll admit to be no closer to the answer. The problem is that once a page is delivered to someone you have no idea what they’re doing unless, and if, they then do something – go to another page of yours, click a button, etc. They could have immediately left the site and gone elsewhere… you simply don’t get back the level of interaction that would tell you this.

So my solution was based on simple maths. Using Google Analytics and the like I work out how long an average user spends looking at a page on the site. Let’s say it’s 90 seconds.

I’m using PHP and MySQL for this example. So, create a new table named users_online and create two fields for it – the first named timestamp and the second ip_address.

With your database already open execute the following PHP, pre-setting the variable $online_seconds with the figure we discussed a couple of sentences ago (in my example, 90). This should be at the top of each page.

$timestamp = time();
$timeout = $timestamp-$online_seconds;
$insert=mysql_query("INSERT INTO users_online VALUES('$timestamp','$REMOTE_ADDR')");
$delete=mysql_query("DELETE FROM users_online WHERE timestamp<'$timeout'");
$result=mysql_query("SELECT DISTINCT ip_address FROM users_online");
$user_num=mysql_num_rows($result);

This will add the period of time (90 seconds) to the current timestamp and insert a row into the table with that as a “timeout”. We then delete any rows where this timeour has now passed. Finally, we read the number of distinct IP addresses – this is the number of users currently online and is returned as $user_num.

How does this work? Well, the idea is that after 90 seconds if the user hasn’t moved onto another page or refreshed the current one then they’re gone. If they do, a new row with their IP address is created and they’re counted once more as still being active. Quite simple really. Possibly not the most accurate but without using host-side JavaScript, for instance, then I’m not sure how you would.

If nothing else it’s handy to have an idea as to how many people are online before you upgrade your site and potentially break it ;)

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